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==References== ==References==


* {{cite journal | last1=Mashreghi | first1=J. | last2=Ransford | first2=T. | title=Binomial sums and functions of exponential type | journal=Bull. London Math. Soc. | volume=37 | number=01 | pages=15–24 | year=2005 | url=http://journals.cambridge.org/action/displayAbstract?fromPage=online&aid=277266}}. * {{cite journal | last1=Mashreghi | first1=J. | last2=Ransford | first2=T. | title=Binomial sums and functions of exponential type | journal=Bull. London Math. Soc. | volume=37 | number=1 | pages=15–24 | year=2005 | doi=10.1112/S0024609304003625 | s2cid=122766740 | url=http://journals.cambridge.org/action/displayAbstract?fromPage=online&aid=277266}}.


{{DEFAULTSORT:Mashreghi-Ransford inequality}} {{DEFAULTSORT:Mashreghi-Ransford inequality}}

Latest revision as of 08:41, 3 January 2023

In Mathematics, the Mashreghi–Ransford inequality is a bound on the growth rate of certain sequences. It is named after J. Mashreghi and T. Ransford.

Let ( a n ) n 0 {\displaystyle (a_{n})_{n\geq 0}} be a sequence of complex numbers, and let

b n = k = 0 n ( n k ) a k , ( n 0 ) , {\displaystyle b_{n}=\sum _{k=0}^{n}{n \choose k}a_{k},\qquad (n\geq 0),}

and

c n = k = 0 n ( 1 ) k ( n k ) a k , ( n 0 ) . {\displaystyle c_{n}=\sum _{k=0}^{n}(-1)^{k}{n \choose k}a_{k},\qquad (n\geq 0).}

Here the binomial coefficients are defined by

( n k ) = n ! k ! ( n k ) ! . {\displaystyle {n \choose k}={\frac {n!}{k!(n-k)!}}.}

Assume that, for some β > 1 {\displaystyle \beta >1} , we have b n = O ( β n ) {\displaystyle b_{n}=O(\beta ^{n})} and c n = O ( β n ) {\displaystyle c_{n}=O(\beta ^{n})} as n {\displaystyle n\to \infty } . Then Mashreghi-Ransford showed that

a n = O ( α n ) {\displaystyle a_{n}=O(\alpha ^{n})} , as n {\displaystyle n\to \infty } ,

where α = β 2 1 . {\displaystyle \alpha ={\sqrt {\beta ^{2}-1}}.} Moreover, there is a universal constant κ {\displaystyle \kappa } such that

( lim sup n | a n | α n ) κ ( lim sup n | b n | β n ) 1 2 ( lim sup n | c n | β n ) 1 2 . {\displaystyle \left(\limsup _{n\to \infty }{\frac {|a_{n}|}{\alpha ^{n}}}\right)\leq \kappa \,\left(\limsup _{n\to \infty }{\frac {|b_{n}|}{\beta ^{n}}}\right)^{\frac {1}{2}}\left(\limsup _{n\to \infty }{\frac {|c_{n}|}{\beta ^{n}}}\right)^{\frac {1}{2}}.}

The precise value of κ {\displaystyle \kappa } is still unknown. However, it is known that

2 3 κ 2. {\displaystyle {\frac {2}{\sqrt {3}}}\leq \kappa \leq 2.}

References

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