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Revision as of 09:57, 28 February 2018 editLegacypac (talk | contribs)Extended confirmed users, Pending changes reviewers158,031 edits Nominated for deletion; see Misplaced Pages:Miscellany for deletion/Draft:Operational Chow ring. (TW)← Previous edit Revision as of 01:09, 9 March 2018 edit undoPremeditated Chaos (talk | contribs)Autopatrolled, Administrators127,856 edits MFD closed as merge (XFDcloser)Next edit →
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{{mfd-mergeto|Chow group|Draft:Operational Chow ring|9 March 2018|Talk:Chow group}}
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The basic question was whether there is a ]: The basic question was whether there is a ]:
:<math>A^*(X) \to \operatorname{H}^*(X, \mathbb{Z}).</math> :<math>A^*(X) \to \operatorname{H}^*(X, \mathbb{Z}).</math>

Revision as of 01:09, 9 March 2018

This page was nominated for deletion. The debate was closed on 9 March 2018 with a consensus to merge the content into the page Chow group. If you find that such action has not been taken promptly, please consider assisting in the merger instead of re-nominating the page for deletion. To discuss the merger, please use the destination page's talk page.

The basic question was whether there is a cycle map:

A ( X ) H ( X , Z ) . {\displaystyle A^{*}(X)\to \operatorname {H} ^{*}(X,\mathbb {Z} ).}

If X is smooth, such a map exists since A ( X ) {\displaystyle A^{*}(X)} is the usual Chow ring of X. (Totaro 2014) harv error: no target: CITEREFTotaro2014 (help) has shown that rationally there is no such a map with good properties even if X is a linear variety, roughly a variety admitting a cell decomposition. He also notes that Voevodsky’s motivic cohomology ring is "probably more useful " than the operational Chow ring for a singular scheme (§ 8 of loc. cit.)


References

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