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Revision as of 07:41, 9 September 2018 editTakuyaMurata (talk | contribs)Extended confirmed users, IP block exemptions, Pending changes reviewers89,986 edits Undid revision 858724104 by JJMC89 (talk) remove G13Tag: Undo← Previous edit Revision as of 02:28, 12 March 2019 edit undoLiz (talk | contribs)Autopatrolled, Checkusers, Oversighters, Administrators768,026 edits Requesting speedy deletion (CSD G13). (TW)Next edit →
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{{mfd-mergeto|Chow group|Draft:Operational Chow ring|9 March 2018|Talk:Chow group}} {{mfd-mergeto|Chow group|Draft:Operational Chow ring|9 March 2018|Talk:Chow group}}



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This draft was nominated by Liz on March 12, 2019.
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This page was last edited by Liz (contribs | logs) at 02:28, 12 March 2019 (UTC) (5 years ago)
This page was nominated for deletion. The debate was closed on 9 March 2018 with a consensus to merge the content into the page Chow group. If you find that such action has not been taken promptly, please consider assisting in the merger instead of re-nominating the page for deletion. To discuss the merger, please use the destination page's talk page.

The basic question was whether there is a cycle map:

A ( X ) H ( X , Z ) . {\displaystyle A^{*}(X)\to \operatorname {H} ^{*}(X,\mathbb {Z} ).}

If X is smooth, such a map exists since A ( X ) {\displaystyle A^{*}(X)} is the usual Chow ring of X. (Totaro 2014) harv error: no target: CITEREFTotaro2014 (help) has shown that rationally there is no such a map with good properties even if X is a linear variety, roughly a variety admitting a cell decomposition. He also notes that Voevodsky’s motivic cohomology ring is "probably more useful " than the operational Chow ring for a singular scheme (§ 8 of loc. cit.)


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