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:<math> \left( \limsup_{n \to \infty} \frac{|a_n|}{\alpha^n} \right) \leq \kappa \, \left( \limsup_{n \to \infty} \frac{|b_n|}{\beta^n} \right)^{\frac{1}{2}} \left( \limsup_{n \to \infty} \frac{|c_n|}{\beta^n} \right)^{\frac{1}{2}}.</math>
:<math> \left( \limsup_{n \to \infty} \frac{|a_n|}{\alpha^n} \right) \leq \kappa \, \left( \limsup_{n \to \infty} \frac{|b_n|}{\beta^n} \right)^{\frac{1}{2}} \left( \limsup_{n \to \infty} \frac{|c_n|}{\beta^n} \right)^{\frac{1}{2}}.</math>
The precise value of <math>\kappa</math> is unknown. However, it is known that
The precise value of <math>\kappa</math> is still unknown. However, it is known that
: <math> \frac{2}{\sqrt{3}}\leq \kappa \leq 2.</math>
: <math> \frac{2}{\sqrt{3}}\leq \kappa \leq 2.</math>
Revision as of 19:30, 20 April 2021
In Mathematics , the Mashreghi–Ransford inequality is a bound on the growth rate of certain sequences . It is named after J. Mashreghi and T. Ransford .
Let
(
a
n
)
n
≥
0
{\displaystyle (a_{n})_{n\geq 0}}
be a sequence of complex numbers , and let
b
n
=
∑
k
=
0
n
(
n
k
)
a
k
,
(
n
≥
0
)
,
{\displaystyle b_{n}=\sum _{k=0}^{n}{n \choose k}a_{k},\qquad (n\geq 0),}
and
c
n
=
∑
k
=
0
n
(
−
1
)
k
(
n
k
)
a
k
,
(
n
≥
0
)
.
{\displaystyle c_{n}=\sum _{k=0}^{n}(-1)^{k}{n \choose k}a_{k},\qquad (n\geq 0).}
We remind that the binomial coefficients are defined by
(
n
k
)
=
n
!
k
!
(
n
−
k
)
!
.
{\displaystyle {n \choose k}={\frac {n!}{k!(n-k)!}}.}
Assume that, for some
β
>
1
{\displaystyle \beta >1}
, we have
b
n
=
O
(
β
n
)
{\displaystyle b_{n}=O(\beta ^{n})}
and
c
n
=
O
(
β
n
)
{\displaystyle c_{n}=O(\beta ^{n})}
as
n
→
∞
{\displaystyle n\to \infty }
. Then Mashreghi-Ransford showed that
a
n
=
O
(
α
n
)
{\displaystyle a_{n}=O(\alpha ^{n})}
, as
n
→
∞
{\displaystyle n\to \infty }
,
where
α
=
β
2
−
1
.
{\displaystyle \alpha ={\sqrt {\beta ^{2}-1}}.}
Moreover, there is a universal constant
κ
{\displaystyle \kappa }
such that
(
lim sup
n
→
∞
|
a
n
|
α
n
)
≤
κ
(
lim sup
n
→
∞
|
b
n
|
β
n
)
1
2
(
lim sup
n
→
∞
|
c
n
|
β
n
)
1
2
.
{\displaystyle \left(\limsup _{n\to \infty }{\frac {|a_{n}|}{\alpha ^{n}}}\right)\leq \kappa \,\left(\limsup _{n\to \infty }{\frac {|b_{n}|}{\beta ^{n}}}\right)^{\frac {1}{2}}\left(\limsup _{n\to \infty }{\frac {|c_{n}|}{\beta ^{n}}}\right)^{\frac {1}{2}}.}
The precise value of
κ
{\displaystyle \kappa }
is still unknown. However, it is known that
2
3
≤
κ
≤
2.
{\displaystyle {\frac {2}{\sqrt {3}}}\leq \kappa \leq 2.}
References
Category :
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