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Revision as of 18:26, 28 November 2022 editJoshuaZ (talk | contribs)Extended confirmed users, Pending changes reviewers, Rollbackers31,657 edits add improve bound due to Burcsi, Czierbus, Farkas← Previous edit Revision as of 18:27, 28 November 2022 edit undoJoshuaZ (talk | contribs)Extended confirmed users, Pending changes reviewers, Rollbackers31,657 editsm Properties: formattingNext edit →
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* Lehmer showed that if any composite solution ''n'' exists, it must be odd, ], and divisible by at least seven distinct primes (i.e. ''ω(n) ≥ 7''). Such a number must also be a ]. * Lehmer showed that if any composite solution ''n'' exists, it must be odd, ], and divisible by at least seven distinct primes (i.e. ''ω(n) ≥ 7''). Such a number must also be a ].
* In 1980, Cohen and Hagis proved that, for any solution ''n'' to the problem, ''n'' > 10<sup>20</sup> and ω(''n'') ≥ 14.<ref name="HBI23">Sándor et al (2006) p.23</ref> * In 1980, Cohen and Hagis proved that, for any solution ''n'' to the problem, ''n'' > 10<sup>20</sup> and ω(''n'') ≥ 14.<ref name="HBI23">Sándor et al (2006) p.23</ref>
* In 1988, Hagis showed that if 3 divides any solution ''n'' then ''n'' > 10<sup>1937042</sup> and ω(''n'') ≥ 298848.<ref name=Guy142>Guy (2004) p.142</ref> This was subsequently improved by Burcsi, Czirbusz, and Farkas, who showed that if if $n$ is a solution, with $3|n$, then <math>\omega(n) \geq 4(10^7)(</math> and that <math> n > 10^{\left(36(10^7)\right) }</math> <ref>{{cite journal |last1=Burcsi, P. , Czirbusz,S., Farkas, G. |title=Computational investigation of Lehmer's totient problem |journal=Ann. Univ. Sci. Budapest. Sect. Comput. |date=2011 |volume=35 |page=43-49}}</ref> * In 1988, Hagis showed that if 3 divides any solution ''n'' then ''n'' > 10<sup>1937042</sup> and ω(''n'') ≥ 298848.<ref name=Guy142>Guy (2004) p.142</ref> This was subsequently improved by Burcsi, Czirbusz, and Farkas, who showed that if if <math>n</math> is a solution, with <math>3|n</math>, then <math>\omega(n) \geq 4(10^7)(</math> and that <math> n > 10^{\left(36(10^7)\right) }</math> <ref>{{cite journal |last1=Burcsi, P. , Czirbusz,S., Farkas, G. |title=Computational investigation of Lehmer's totient problem |journal=Ann. Univ. Sci. Budapest. Sect. Comput. |date=2011 |volume=35 |page=43-49}}</ref>
* The number of solutions to the problem less than <math>X</math> is at most <math>{X^{1/2}/(\log X)^{1/2+o(1)}}</math>.<ref name=LP2011>Luca and Pomerance (2011)</ref> * The number of solutions to the problem less than <math>X</math> is at most <math>{X^{1/2}/(\log X)^{1/2+o(1)}}</math>.<ref name=LP2011>Luca and Pomerance (2011)</ref>



Revision as of 18:27, 28 November 2022

For Lehmer's Mahler measure problem, see Lehmer's conjecture. Unsolved problem in mathematics: Can the totient function of a composite number n {\displaystyle n} divide n 1 {\displaystyle n-1} ? (more unsolved problems in mathematics)

In mathematics, Lehmer's totient problem asks whether there is any composite number n such that Euler's totient function φ(n) divides n − 1. This is an unsolved problem.

It is known that φ(n) = n − 1 if and only if n is prime. So for every prime number n, we have φ(n) = n − 1 and thus in particular φ(n) divides n − 1. D. H. Lehmer conjectured in 1932 that there are no composite numbers with this property.


Properties

  • Lehmer showed that if any composite solution n exists, it must be odd, square-free, and divisible by at least seven distinct primes (i.e. ω(n) ≥ 7). Such a number must also be a Carmichael number.
  • In 1980, Cohen and Hagis proved that, for any solution n to the problem, n > 10 and ω(n) ≥ 14.
  • In 1988, Hagis showed that if 3 divides any solution n then n > 10 and ω(n) ≥ 298848. This was subsequently improved by Burcsi, Czirbusz, and Farkas, who showed that if if n {\displaystyle n} is a solution, with 3 | n {\displaystyle 3|n} , then ω ( n ) 4 ( 10 7 ) ( {\displaystyle \omega (n)\geq 4(10^{7})(} and that n > 10 ( 36 ( 10 7 ) ) {\displaystyle n>10^{\left(36(10^{7})\right)}}
  • The number of solutions to the problem less than X {\displaystyle X} is at most X 1 / 2 / ( log X ) 1 / 2 + o ( 1 ) {\displaystyle {X^{1/2}/(\log X)^{1/2+o(1)}}} .

References

  1. Lehmer (1932)
  2. Sándor et al (2006) p.23
  3. Guy (2004) p.142
  4. Burcsi, P. , Czirbusz,S., Farkas, G. (2011). "Computational investigation of Lehmer's totient problem". Ann. Univ. Sci. Budapest. Sect. Comput. 35: 43-49.{{cite journal}}: CS1 maint: multiple names: authors list (link)
  5. Luca and Pomerance (2011)
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