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1940 United States presidential election in Rhode Island

← 1936 November 5, 1940 1944 →

Nominee Franklin D. Roosevelt Wendell Willkie Party Democratic Republican Home state New York New York Running mate Henry A. Wallace Charles L. McNary Electoral vote 4 0 Popular vote 182,182 138,653 Percentage 56.73% 43.17%

County Results Municipality Results Roosevelt   50-60%   60-70%   70-80% Willkie   50-60%   60-70%   70-80%   80-90%

President before election Franklin D. Roosevelt Democratic Elected President Franklin D. Roosevelt Democratic

Elections in Rhode Island
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The 1940 United States presidential election in Rhode Island took place on November 5, 1940. All contemporary 48 states were part of the 1940 United States presidential election. State voters chose four electors to the Electoral College, which selected the president and vice president.

Rhode Island was won by incumbent Democratic President Franklin D. Roosevelt of New York, who was running against Republican businessman Wendell Willkie of New York. Roosevelt ran with former Secretary of Agriculture Henry A. Wallace of Iowa as his running mate, and Willkie ran with Senator Charles L. McNary of Oregon.

Roosevelt won Rhode Island by a margin of 13.56%. Rhode Island was one of six states that swung more Democratic compared to 1936, alongside Delaware, New Hampshire, Maine, Vermont, and North Carolina.

Results

By county

See also

• United States presidential elections in Rhode Island

References

1. "1940 Presidential General Election Results – Rhode Island". U.S. Election Atlas. Retrieved December 23, 2013.
2. "RI.gov: Election Results". www.ri.gov. Retrieved February 11, 2024.

v t e State and district results of the 1940 United States presidential election
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