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Serre's inequality on height

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In algebra, specifically in the theory of commutative rings, Serre's inequality on height states: given a (Noetherian) regular ring A and a pair of prime ideals p , q {\displaystyle {\mathfrak {p}},{\mathfrak {q}}} in it, for each prime ideal r {\displaystyle {\mathfrak {r}}} that is a minimal prime ideal over the sum p + q {\displaystyle {\mathfrak {p}}+{\mathfrak {q}}} , the following inequality on heights holds:

ht ( r ) ht ( p ) + ht ( q ) . {\displaystyle \operatorname {ht} ({\mathfrak {r}})\leq \operatorname {ht} ({\mathfrak {p}})+\operatorname {ht} ({\mathfrak {q}}).}

Without the assumption on regularity, the inequality can fail; see scheme-theoretic intersection#Proper intersection.

Sketch of Proof

Serre gives the following proof of the inequality, based on the validity of Serre's multiplicity conjectures for formal power series ring over a complete discrete valuation ring.

By replacing A {\displaystyle A} by the localization at r {\displaystyle {\mathfrak {r}}} , we assume ( A , r ) {\displaystyle (A,{\mathfrak {r}})} is a local ring. Then the inequality is equivalent to the following inequality: for finite A {\displaystyle A} -modules M , N {\displaystyle M,N} such that M A N {\displaystyle M\otimes _{A}N} has finite length,

dim A M + dim A N dim A {\displaystyle \dim _{A}M+\dim _{A}N\leq \dim A}

where dim A M = dim ( A / Ann A ( M ) ) {\displaystyle \dim _{A}M=\dim(A/\operatorname {Ann} _{A}(M))} = the dimension of the support of M {\displaystyle M} and similar for dim A N {\displaystyle \dim _{A}N} . To show the above inequality, we can assume A {\displaystyle A} is complete. Then by Cohen's structure theorem, we can write A = A 1 / a 1 A 1 {\displaystyle A=A_{1}/a_{1}A_{1}} where A 1 {\displaystyle A_{1}} is a formal power series ring over a complete discrete valuation ring and a 1 {\displaystyle a_{1}} is a nonzero element in A 1 {\displaystyle A_{1}} . Now, an argument with the Tor spectral sequence shows that χ A 1 ( M , N ) = 0 {\displaystyle \chi ^{A_{1}}(M,N)=0} . Then one of Serre's conjectures says dim A 1 M + dim A 1 N < dim A 1 {\displaystyle \dim _{A_{1}}M+\dim _{A_{1}}N<\dim A_{1}} , which in turn gives the asserted inequality. {\displaystyle \square }

References

  1. Serre 2000, Ch. V, § B.6, Theorem 3.
  2. Fulton 1998, § 20.4.
  3. Serre 2000, Ch. V, § B. 6.


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