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All 6 Arizona seats to the United States House of Representatives | ||||||||||||||||||||||||||||
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The 1998 congressional elections in Arizona were elections for Arizona's delegation to the United States House of Representatives, which occurred along with congressional elections nationwide on November 7, 1998. Arizona has six seats, as apportioned during the 1990 United States census. Republicans held five seats and Democrats held one seat.
Overview
1998 United States House of Representatives elections in Arizona | |||||
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Party | Votes | Percentage | Seats | +/– | |
Republican | 573,651 | 57.15% | 5 | - | |
Democratic | 406,834 | 40.53% | 1 | - | |
Libertarian | 18,042 | 1.80% | 0 | - | |
Others | 5,239 | 0.52% | 0 | - | |
Totals | 1,003,766 | 100.00% | 6 | - |
References
- "Statistics report" (PDF). clerk.house.gov. 1998. Retrieved March 30, 2021.
Elections in Arizona | |||||
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Governor | |||||
Attorney General | |||||
Secretary of State | |||||
State Treasurer | |||||
Superintendent of Public Instruction | |||||
U.S. President | |||||
U.S. Senate |
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U.S. House | |||||
See also: Political party strength in Arizona |
(1997 ←) 1998 United States elections (→ 1999) | |
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U.S. Senate |
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U.S. House |
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Governors |
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Attorneys General | |
State legislatures | |
State officials | |
States generally |
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Mayors |