Main article: 1836 United States presidential election
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 County Results
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The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.
Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%. The result would ultimately prove decisive in Van Buren's victory; had Harrison won the state, then Van Buren would not have achieved a majority in the Electoral College, meaning that the election would have been decided in the House of Representatives.
Results
| 1836 United States presidential election in Pennsylvania | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Martin Van Buren | 91,457 | 51.18% | 30 | |
| Whig | William Henry Harrison | 87,235 | 48.82% | 0 | |
| Totals | 178,692 | 100.0% | 30 | ||
See also
References
- "1836 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.
| State and district results of the 1836 United States presidential election | ||
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