Misplaced Pages

Saturated measure

Article snapshot taken from Wikipedia with creative commons attribution-sharealike license. Give it a read and then ask your questions in the chat. We can research this topic together.
(Redirected from Locally measurable set) Measure in mathematics

In mathematics, a measure is said to be saturated if every locally measurable set is also measurable. A set E {\displaystyle E} , not necessarily measurable, is said to be a locally measurable set if for every measurable set A {\displaystyle A} of finite measure, E A {\displaystyle E\cap A} is measurable. σ {\displaystyle \sigma } -finite measures and measures arising as the restriction of outer measures are saturated.

References

  1. Bogachev, Vladmir (2007). Measure Theory Volume 2. Springer. ISBN 978-3-540-34513-8.
Measure theory
Basic concepts
Sets
Types of measures
Particular measures
Maps
Main results
Other results
For Lebesgue measure
Applications & related
Stub icon

This mathematical analysis–related article is a stub. You can help Misplaced Pages by expanding it.

Categories: