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Schröder–Bernstein theorems for operator algebras

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The Schröder–Bernstein theorem from set theory has analogs in the context operator algebras. This article discusses such operator-algebraic results.

For von Neumann algebras

Suppose M is a von Neumann algebra and E, F are projections in M. Let ~ denote the Murray-von Neumann equivalence relation on M. Define a partial order « on the family of projections by E « F if E ~ F' F. In other words, E « F if there exists a partial isometry UM such that U*U = E and UU*F.

For closed subspaces M and N where projections PM and PN, onto M and N respectively, are elements of M, M « N if PM « PN.

The Schröder–Bernstein theorem states that if M « N and N « M, then M ~ N.

A proof, one that is similar to a set-theoretic argument, can be sketched as follows. Colloquially, N « M means that N can be isometrically embedded in M. So

M = M 0 N 0 {\displaystyle M=M_{0}\supset N_{0}}

where N0 is an isometric copy of N in M. By assumption, it is also true that, N, therefore N0, contains an isometric copy M1 of M. Therefore, one can write

M = M 0 N 0 M 1 . {\displaystyle M=M_{0}\supset N_{0}\supset M_{1}.}

By induction,

M = M 0 N 0 M 1 N 1 M 2 N 2 . {\displaystyle M=M_{0}\supset N_{0}\supset M_{1}\supset N_{1}\supset M_{2}\supset N_{2}\supset \cdots .}

It is clear that

R = i 0 M i = i 0 N i . {\displaystyle R=\cap _{i\geq 0}M_{i}=\cap _{i\geq 0}N_{i}.}

Let

M N = d e f M ( N ) . {\displaystyle M\ominus N{\stackrel {\mathrm {def} }{=}}M\cap (N)^{\perp }.}

So

M = i 0 ( M i N i ) j 0 ( N j M j + 1 ) R {\displaystyle M=\oplus _{i\geq 0}(M_{i}\ominus N_{i})\quad \oplus \quad \oplus _{j\geq 0}(N_{j}\ominus M_{j+1})\quad \oplus R}

and

N 0 = i 1 ( M i N i ) j 0 ( N j M j + 1 ) R . {\displaystyle N_{0}=\oplus _{i\geq 1}(M_{i}\ominus N_{i})\quad \oplus \quad \oplus _{j\geq 0}(N_{j}\ominus M_{j+1})\quad \oplus R.}

Notice

M i N i M N for all i . {\displaystyle M_{i}\ominus N_{i}\sim M\ominus N\quad {\mbox{for all}}\quad i.}

The theorem now follows from the countable additivity of ~.

Representations of C*-algebras

There is also an analog of Schröder–Bernstein for representations of C*-algebras. If A is a C*-algebra, a representation of A is a *-homomorphism φ from A into L(H), the bounded operators on some Hilbert space H.

If there exists a projection P in L(H) where P φ(a) = φ(a) P for every a in A, then a subrepresentation σ of φ can be defined in a natural way: σ(a) is φ(a) restricted to the range of P. So φ then can be expressed as a direct sum of two subrepresentations φ = φ' σ.

Two representations φ1 and φ2, on H1 and H2 respectively, are said to be unitarily equivalent if there exists a unitary operator U: H2H1 such that φ1(a)U = 2(a), for every a.

In this setting, the Schröder–Bernstein theorem reads:

If two representations ρ and σ, on Hilbert spaces H and G respectively, are each unitarily equivalent to a subrepresentation of the other, then they are unitarily equivalent.

A proof that resembles the previous argument can be outlined. The assumption implies that there exist surjective partial isometries from H to G and from G to H. Fix two such partial isometries for the argument. One has

ρ = ρ 1 ρ 1 σ 1 where σ 1 σ . {\displaystyle \rho =\rho _{1}\simeq \rho _{1}'\oplus \sigma _{1}\quad {\mbox{where}}\quad \sigma _{1}\simeq \sigma .}

In turn,

ρ 1 ρ 1 ( σ 1 ρ 2 ) where ρ 2 ρ . {\displaystyle \rho _{1}\simeq \rho _{1}'\oplus (\sigma _{1}'\oplus \rho _{2})\quad {\mbox{where}}\quad \rho _{2}\simeq \rho .}

By induction,

ρ 1 ρ 1 σ 1 ρ 2 σ 2 ( i 1 ρ i ) ( i 1 σ i ) , {\displaystyle \rho _{1}\simeq \rho _{1}'\oplus \sigma _{1}'\oplus \rho _{2}'\oplus \sigma _{2}'\cdots \simeq (\oplus _{i\geq 1}\rho _{i}')\oplus (\oplus _{i\geq 1}\sigma _{i}'),}

and

σ 1 σ 1 ρ 2 σ 2 ( i 2 ρ i ) ( i 1 σ i ) . {\displaystyle \sigma _{1}\simeq \sigma _{1}'\oplus \rho _{2}'\oplus \sigma _{2}'\cdots \simeq (\oplus _{i\geq 2}\rho _{i}')\oplus (\oplus _{i\geq 1}\sigma _{i}').}

Now each additional summand in the direct sum expression is obtained using one of the two fixed partial isometries, so

ρ i ρ j and σ i σ j for all i , j . {\displaystyle \rho _{i}'\simeq \rho _{j}'\quad {\mbox{and}}\quad \sigma _{i}'\simeq \sigma _{j}'\quad {\mbox{for all}}\quad i,j\;.}

This proves the theorem.

See also

References

  • B. Blackadar, Operator Algebras, Springer, 2006.
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